Answer 1:
The reaction involved in present case is
HCl + NaOH → NaCl + H2O
In present case, it can be seen that 1 mole of HCl reacts with 1 mole of NaOH to give 1 mole of NaCl and H2O.
We know that, number of mole = weight of substance (g)/molecular weight
For HCl, number of mole = 30/36.5 = 0.8219
For NaOH, number of mole that can be produced = 0.8219
Thus, theoretical yield of NaOH = number of mole X Molecular weigh
= 0.8219 X 58.5
= 48.08 g.
Theoretical yield of the experiment is 48.08 g.
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Answer 2:
Percent yield is mathematically expressed as,
[tex] \frac{\text{Actual Yeild}}{\text{Theoretical Yield}} X 100[/tex]
In present case, Actual Yield = 10 g
Theoretical Yield = 48.08 g.
Therefore, Percent yield = [tex] \frac{\text{10}}{\text{48.08}} X 100[/tex]
= 20.79%
Thus, percent yield of the experiment is 20.79 %
