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You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t^2 + 541. What is the height of the rock after 2 seconds?

Respuesta :

carlosego
For this case we have the following equation:
 [tex]h = -16t ^ 2 + 541 [/tex]
 To answer the question, what we must do is evaluate the function for t = 2.
 We have then:
 [tex]h = -16 (2) ^ 2 + 541 [/tex]
 Rewriting we have:
 [tex]h = -16 (4) + 541 h = -64 + 541 h = 477 feet[/tex]
 Answer:
 The height of the rock after 2 seconds is:
 [tex]h = 477 feet[/tex]

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