Respuesta :
y = sqrt(x - 5) - 1
for the square root to be a real number x must be >= 5
The domain is x>= 5 , or in interval notation [5, ∞)
for the square root to be a real number x must be >= 5
The domain is x>= 5 , or in interval notation [5, ∞)
Answer:
The function domain is
[tex]x\ge \:5[/tex] Or in interval notation [5, ∞)
Step-by-step explanation:
we need to find the domain of [tex]y = \sqrt{x-5}-1[/tex]
Domain definition :-The domain of a function is the set of input or argument values for which the function is real and defined
[tex]\mathrm{Find\:non-negative\:values\:for\:radicals}:\quad x\ge \:5[/tex]
[tex]\mathrm{Solve\:}\:x-5\ge \:0:\quad x\ge \:5[/tex]
The function domain is
[tex]x\ge \:5[/tex] Or in interval notation [5, ∞)
