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A beam of light enters a flat pane of glass with parallel and smooth surfaces at an angle of incidence of 300. the refractive index of the glass is 1.2. the light is refracted when it enters the glass plate and refracted again when it leaves. what is the exiting angle of refraction? answer in degrees but do not enter the unit.

Respuesta :

Angle of refraction is calculated by Snell's law

it is given as

[tex]n_1sin i = n_2 sinr[/tex]

now for the first surface we can say

[tex]1* sin30 = 1.2 * sinr[/tex]

[tex] r = 24.6 degree[/tex]

now this is the angle of incidence on the next surface

so we will again apply snell's law

[tex]n_1sin i = n_2 sinr[/tex]

[tex]1.2* sin24.6 = 1 * sinr[/tex]

[tex] r = 30 degree[/tex]

so the final angle of refraction after two refraction will be same as that of angle of incidence.

So its 30 degree.

facundo3141592

Using Snell's law we will see that the exiting angle is equal to 30°.

What is the exiting angle of refraction?

Remember that Snell's law says that:

n₁*sin(θ₁) = n₂*sin(θ₂)

  • n₁ is the refractive index of the first medium, that we assume is air, so n₁ = 1.
  • θ₁ is the incidence angle, so θ₁ = 30°
  • n₂ is the refractive index of the second material, we know that n₂ = 1.2
  • And finally, θ₂ is the first refraction angle.

The we can solve:

sin(30°) = 1.2*sin(θ₂)

θ₂ = Asin( sin(30°)/1.2) = 24.6°

Then the angle of incidence in the other surface of the material will be 24.6°, and we will need to solve:

1.2*sin(24.6°) = 1*sin(θ₃)

We will get:

θ₃ = Asin(1.2*sin(24.6°)) = 30°

What does this mean?

That the angle of incidence and the exiting angles are always the same when the initial and final materials have the same refractive index.

If you want to learn more about Snell's law, you can read:

https://brainly.com/question/10112549

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