In this question we need to use the compound interest formula, which is
[tex] A= P(1+r)^n [/tex]
A represents the amount after n years and P is the principal.
And in this question, P = 2000, n =10 years, r is unknown and A = 3600.
Substituting these values in the formula
[tex] 3600 = 2000(1+r)^{10} [/tex]
[tex] \frac{9}{5} = (1+r)^{10} [/tex]
[tex] 1+r = ( \frac{9}{5})^{1/10} [/tex]
1+r = 1.06054
r=0.06054 or approx 6%
