Respuesta :
When three resistors are connected in series then total equivalent of all three is given by
[tex]R_{eq}= R_1 + R_2 + R_3[/tex]
Also in this case current is given by
[tex]i = \frac{V}{R_{eq}[/tex]
Now if one of the resistance is removed
Then
[tex]R_{eq} = R_1 + R_2[/tex]
let one of the resistance is removed
while current flowing in the open circuit will be given by
[tex]i = \frac{V}{R_{eq}}[/tex]
So here since resistance is decreased then current must be increased in the circuit.
Hello! The equivalent resistance in a series circuit equals to the sum of all the resistors in the circuit.
So it’s R1+R2+R3
After u remove one of the resistors from the circuit, the equivalent becomes R1+R2, so it decreases.
The current in a series circuit will not change as the resistors change. It holds constant so there’ll be no change to the current.
Hope this helps:)
So it’s R1+R2+R3
After u remove one of the resistors from the circuit, the equivalent becomes R1+R2, so it decreases.
The current in a series circuit will not change as the resistors change. It holds constant so there’ll be no change to the current.
Hope this helps:)