contestada

A rectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t in the y-z plane that makes an angle of 30o with the y-axis. what is the flux through the loop.

Respuesta :

area vector of the loop is given by

[tex]A = 0.08 * 0.03 (k)[/tex]

area vector is always perpendicular to the plane of the loop

[tex]A = 24 * 10^{-4} (k)[/tex]

now the magnetic field vector is given as

[tex]B = 4.5 (cos30 (j) + sin30 (k))[\tex]

[tex]B = 3.89 j + 2.25 k[/tex]

now the magnetic flux is given by

[tex]\phi = B. A[\tex]

[tex]\phi = (3.89 j + 2.25 k ).(24 * 10^{-4} k)[/tex]

[tex]\phi = 5.4 * 10^{-3} Wb[/tex]