Answer: -
In the acetylene torch, 7.5 moles of O₂ are needed to react with 3.00 moles of acetylene gas C₂H₂.
Explanation: -
The balanced chemical equation for this reaction is
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
From the equation we see
2 moles of C₂H₂ react with 5 moles of O₂
3.00 moles of C₂H₂ react with [tex] \frac{5 moles of O2}{2 moles of C2H2} [/tex] x 3.00 moles of C₂H₂
= 7.5 moles of O₂
Thus, in the acetylene torch, 7.5 moles of O₂ are needed to react with 3.00 moles of acetylene gas C₂H₂.
