"a box contains" eight chocolates -- two "with pecans", five with coconut, and one with raspberry creme. spider-man eats three of the chocolates, chosen randomly. "what's the probability that he eats" (exactly) one with coconut

Respuesta :

[tex] \displaystyle
|\Omega|=\binom{8}{3}=\dfrac{8!}{3!5!}=\dfrac{6\cdot7\cdot8}{2\cdot3}=56\\
|A|=5\cdot\binom{3}{2}=5\cdot3=15\\\\
P(A)=\dfrac{15}{56}\approx27\% [/tex]

The probability that the spider - man eats exactly one chocolate with coconut is 0.268.

What is probability?

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1.

Given -

Total number of chocolates = 8

Number of chocolates with coconut = 5

Number of chocolates without coconut = Number of chocolates with pecans or raspberry = 2 + 1 = 3

Number of ways of choosing 3 chocolates out of 8 = [tex]{8}_C_{3}[/tex] = 56

Number of ways of choosing 1 chocolate out of 3 coconut chocolates and 2 chocolates out of 5 non coconut chocolates = [tex]{3}_C_{1} * {5}_C_{2}[/tex] = 3 x 5 = 15

Probability that spider man will eat exactly one chocolate with coconut =  

= [tex]\frac{Favourable\ number\ of outcomes}{Total\ number\ of\ outcomes}[/tex] = [tex]\frac{15}{56}[/tex]  = 0.268

Learn more about probability here

https://brainly.com/question/11234923

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