In this question, we have to use the formula of volume of sphere, which is
[tex]V= \frac{4}{3} \pi r^3[/tex]
S for gumball, volume is
[tex]= \frac{4}{3}* \pi (27)^3 = 82447.96 mm^3[/tex]
Volume of the gumball's spherical hollow core is
[tex]= \frac{4}{3}* \pi*23^3=50965.01mm^3[/tex]
Required volume is the difference of the volume of gumball and gumball's spherical hollow core, that is
[tex]V=82447.96-50965.01= 31482.95 mm^3[/tex]
