Here mass is floating on the piston at equilibrium
So it will have constant pressure always remains constant
So final pressure is same as initial pressure = 900 kPa
now we can say
[tex]\frac{V_1}{V_2} = \frac{T_1}{T_2}[/tex]
[tex]\frac{1}{V_2} = \frac{273+10}{273+50}[/tex]
[tex]V_2 = 1.14 m^3[/tex]
so final pressure is 900 kPa and final volume is 1.14 m^3