A person has always enjoyed eating tuna fish. Unfortunately, a recent study of the mercury content of canned tuna found that chunk white tuna contains 0.67 ppm hg. The u.S. Environmental protection agency recommends no more than 0.1 μg hg/kg body weight per day. If the person weighs 72 kg, how often may he/she eat a can containing 6 ounces (1 lb = 16 oz) of chunk white tuna so that he/she does not average more than 0.1 μg hg/kg body weight per day?

Respuesta :

According to the Food and Drug Administration, five of the most generally consumed fish, which are low in mercury content are canned light tuna, shrimp, catfish, pollock, and salmon. However, another commonly consumed fish, that is, white tuna or albacore exhibits more mercury in comparison to the light canned tuna.  

In the given case, mass of tuna is 6 oz = 6 × 28.3495 = 170.097 grams

Maximum mass of Hg permitted for 72 Kg body weight per day will be,  

= 72 × 0.1 = 7.2 micrograms in a day

The concentration of white tuna in Hg = 0.67 ppm = 0.67 × 10^ (-6)

Mass of Hg = concentration × mass

= 0.67 × 10 ^ (-6) × 170.97

= 113.96 micrograms

Time between the consumption = 113.96 ÷ 7.2

= 16 days, that is, once in every 16 days.  


Answer:

The answer is in 16 days.

Explanation:

Please see the solution in the attached Word document

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