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A lab technician needs to create 570.0 milliliters of a 2.00 M solution of magnesium chloride (MgCl2). To make this solution, how many grams of magnesium chloride does the technician need?
Refer to the periodic table for help. Express your answer to three significant figures.

The required mass is grams.

Respuesta :

This question needs to use the molarity equation, [tex]M=\frac{n}{V}[/tex], where M is molarity, n is number of moles and V is the volume. With this equation we can find the number of moles. The volume of 570ml should be converted to L for correct units.

[tex]n=MV= \frac{2mol}{L}\times 570ml \times \frac{L}{1000ml}= 1.14mol[/tex]

Multiply the number of moles by the molecular mass of [tex]MgCl_2[/tex] which is 95.21 g/mol to get the mass.

[tex]1.14 mol Mg(Cl_2) \times\frac{95.21 g}{mol} = 108 g[/tex].

109 for brainly just did it 5/5 correct (Three significant figures)