Answer : The energy of one photon of light is [tex]4.747\times 10^{-19}J[/tex].
Solution : Given,
Frequency = [tex]7.16\times 10^{14}Hz=7.16\times 10^{14}s[/tex] (1Hz = 1 second period)
Formula used :
[tex]E=h\nu[/tex]
where,
E = energy
h = Planck's constant = [tex]6.63\times 10^{-34}J/s[/tex]
[tex]\nu[/tex] = frequency
Now put the given values in above formula, we the value for energy of one photon.
[tex]E=(6.63\times 10^{-34}J/s)\times (7.16\times 10^{14}s)=4.747\times 10^{-19}J[/tex]
Therefore, the energy of one photon of light is [tex]4.747\times 10^{-19}J[/tex].
