Answer-
The probability of drawing an O and a B is 0.033
Solution-
Total number of letter in the word “PROBABILITY” is 11
Total number of B in the word is 2
Total number of O in the word is 1
So, as the tiles are chosen with replacement,
[tex]P(B)=\dfrac{2}{11},\ P(O)=\dfrac{1}{11}[/tex]
Now, as two tiles are drawn, so the probability of choosing an “O” and a “B” is,
[tex]=P(O).P(B)+P(B).P(O)[/tex]
Putting the values,
[tex]=P(O).P(B)+P(B).P(O)[/tex]
[tex]=(\dfrac{1}{11}\times \dfrac{2}{11})+(\dfrac{2}{11}\times \dfrac{1}{11})[/tex]
[tex]=\dfrac{2}{121}+\dfrac{2}{121}[/tex]
[tex]=\dfrac{4}{121}[/tex]
[tex]=0.033[/tex]
