Answer:
The mean increased by $1.5 and percent increase is 42.85%.
Step-by-step explanation:
Formula for mean:
[tex]Mean=\frac{\sum x}{n}[/tex]
It is given that Grant spent $2.50, $4.00, $4.25, and $3.25 on breakfast one week.
Total money spent by him in first week is
[tex]2.50+4.00+4.25+3.25=14[/tex]
Mean for first week is
[tex]Mean_1=\frac{14}{4}=3.5[/tex]
The next week he spent $6 more in total for the 4 breakfasts than the week before.
Total money spent by him in second week is
[tex]14+6=20[/tex]
Mean for second week is
[tex]Mean_1=\frac{20}{4}=5[/tex]
Increase in mean
[tex]5-3.5=1.5[/tex]
Therefore the mean increased by $1.5.
Percent increase in mean is
[tex]\%change=\frac{Mean_2-Mean_1}{Mean_1}\times 100[/tex]
[tex]\%change=\frac{1.5}{3.5}\times 100\approx 42.85[/tex]
Therefore the mean increased by $1.5 and percent increase is 42.85%.
