Problem 1
Answers: (-4,-12); (1,-2); (2,-18)
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The x coordinates of the relative min and max are x = -3 and x = 1/3 = 0.33 respectively. Any point that has an x coordinate between these two values will be on an increasing interval. Going from a relative min to a relative max means we go uphill. Anything outside this interval will be on a deceasing interval. The points outside this interval are (-4,-12) and (1,-2) and (2,-18)
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Problem 2
Answer that goes in the blank: 7
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Use the log rules
log(x)+log(y) = log(x*y)
log(x)-log(y) = log(x/y)
to get the following
log(14/3) + log(11/5) - log(22/15)
log((14/3)*(11/5)) - log(22/15)
log(154/15) - log(22/15)
log((154/15)/(22/15))
log((154/15)*(15/22))
log(154/22)
log(7)
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Problem 3
Answer: see the attached image below
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The rule is that log(b,x) = y turns into b^y = x, where b is the base of the log and exponent
So log(2,x) = 5 turns into x = 2^5 = 32. The same applies for the others as well.
Note: log(3,x) = 1 turns into x = 3^1 = 3, but x = 3 isn't listed as an answer
