the center of a circle of a circle is at Q(0,6), a radius is drawn from Q to P(4,6). what are the coordinates of the endpoint of the diameter that includes segment PQ?


A. (0,2)

b. (0,10)

c. (-4,6)

d. (6,-4)

Respuesta :

Answer:

(-4,6) or C

Step-by-step explanation:

Givens

  • x_center = 0
  • y_center = 6
  • x_center = (x1 + x2)/2
  • y_center = (y1 + y2)/2
  • x1 = 4
  • y1 = 6
  • Solve for x2 and y2

Solution

  • x_center = (4 + x2) / 2 = 0                Multiply both sides by 2
  • 0*2 = (4 + x2)*2                                 Divide by 2
  • 0 = 4 + x2                                           Subtract 4 from both sides.
  • -4 = x2
  • You can now declare an answer. The answer must be C

Discussion

  • A and B both have an x value of 0. Not correct.
  • D is backwards.
  • Just to make sure, we'll solve for y2
  • y_center = 6
  • 6 = (y1 + y2)/2         Multiply by 2
  • 6*2 = y1 + y2          Comgine
  • 12 = 6 + y2              Subtract 6 from both sides
  • 12-6 = y2
  • y2 = 6
  • Which is just what C says.