Answer:
A & B
Step-by-step explanation:
[tex]\frac{1}{sin^2x}=4[/tex] can be solved by inverting the fraction and taking the square root.
[tex]\frac{1}{sin^2x}=4\\\\sin^2x=\frac{1}{4}\\\sqrt{sin^2x}=\sqrt{\frac{1}{4} } \\ sin x=\frac{1}{2}[/tex]
We need an x value that gives 1/2 as its sine value. This means we're referring to a triangle with side measures 1, [tex]\sqrt{3}[/tex] and 2. This special triangle has angles 30, 60, and 90. 1/2 matches to a 30 degree angle. All of the options are variations on 30 degrees but not all give the same value.
Sin 30 = 1/2
Sin 150 = 1/2
Sin 210 =-- 1/2
Sin 330 =- 1/2
