Respuesta :

offguard

36y=5y^2+9y

5y^2-27y=0

y(5y-27)=0

y=0 or 5y=27 ⇒y=[tex]\frac{27}{5}[/tex]


From step 3 to step 4, you must use the 0 property rule that says that is the product of 2 (may vary) roots equals 0, then the roots are when each factor equals 0.

wegnerkolmp2741o

Answer:

y=0 and y = 27/5

Step-by-step explanation:

36y=y(5y+9)

Distribute

36y = 5y^2 +9y

Subtract 9y from each side

36y-9y = 5y^2 +9y-9y

27 y = 5y^2

Subtract 27 y from each side

27 y-27y = 5y^2-27y

0 =  5y^2-27y

Factor out y

0 =y(  5y-27)

Using the zero product property

y= 0 and 5y-27= 0

              Add 27 to each side

              5y -27+27 = 27

                5y = 27

               Divide by 5

             5y=/5 = 27/5

                y =27/5