Answer: [tex] - 3.4 \times 10^{-3} N[/tex]
Explanation:
From Newton's law of motion, Force is equal to rate of change of momentum.
The initial velocity of the ball, u = 4.1 m/s
mass of the ball, m = 0.07 kg
During contact, velocity = 0
Time of contact, t = 72 ms = 72 × 10⁻³ s
[tex]F = \frac{m(v-u)}{t} = \frac{0.07 kg \times (0-4.1 m/s)}{72 \times 10^{-3}s} = - 3.4 \times10^{-3} N[/tex]
Thus, net force applied to the ball during this collision is [tex] - 3.4 \times 10^{-3} N[/tex]
