Answer: she invested $3250 in 5% interest account and $6750 in 8% interest account.
Step-by-step explanation:
Let P be the amount Maria invested in an account with 5% interest , then 10,000-P denote the amount invested in account with 8% interest.
The simple interest on amount P with rate r % in time t is given by:-
[tex]I=P\frac{r}{100}t[/tex]
Interest in 5% account in 1 year=[tex]P(\frac{5}{100})(1)=0.05P[/tex]
Similarly,
Interest in 8% account in 1 year=[tex](10,000-P)(\frac{8}{100})(1)=800-0.08P[/tex]
According to the question,
[tex]0.05P+800-0.08P=702.50\\\Rightarrow-0.03P=702.50-800\Rightarrow\ -0.03P=-97.5\\\Rightarrow\ P=\frac{97.5}{0.03}\\\Rightarrow\ P=3,250\\\\10,000-3250=6750[/tex]
Thus, she invested $3250 in 5% interest account and $6750 in 8% interest account.
