Answer:
As per the statement:
Let Event A represents the probability that a vehicle is white and Event B represents the probability that it is a pick up truck .
then;
[tex]P(A) = 0.25[/tex] and [tex]P(B) = 0.15[/tex]
It is also given that:
The Probability that it is a white pick up truck is 0.06.
⇒[tex]P(A \cap B) = 0.06[/tex] where [tex]A \cap B[/tex] represents that it is white pick up truck.
We have to find the the probability that the vehicle is white {given that the vehicle is a pickup truck}
We use the formula:
[tex]P(A/B) = \frac{P(A \cap B)}{P(B)}[/tex]
where
[tex]A/B[/tex] represents that the pick up truck vehicle is white.
Substitute the given values we get;
[tex]P(A/B) = \frac{0.06}{0.15} = 0.4[/tex]
Therefore, the probability that the vehicle is white, given that the vehicle is a pickup truck is 0.4
