Answer: The correct answer is option D.
Explanation:
Mass of the NaCl = 225 g
Volume of the solution ,V = 0.25 L
[tex]Molarity=\frac{\text{Mass of the NaCl}}{\text{Molar mass of the NaCl}\times V(L)}=\frac{225 g}{58.44 g/mol\times 0.25 L}=15.4004 mol/L[/tex]
15.4004 mol/L is the molarity of the solution. The most closest option to our answer is option D.