Answer:
See below.
Step-by-step explanation:
The standard deviation = √ (∑(x - 10)^2 / 8 ) must be approximately = 1 if we take the mean to be 10.
This requires ∑ (x - 10)^2 to be approximately equal to 8.
The following data set would fit the bill:
8.6 9 9 10 10 11 11 11.5.
The values of (x - 10)^2 could be 1.96, 1, 1, 0,0, 1, 1, 2.25 = 8.21
This would give a mean of about 10 and standard deviation of about 1.
