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The magnitude, M, of an earthquake is defined to be m=log l/s, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable. What is the magnitude of an earthquake that is 1,000 times more intense than a standard earthquake? Use a calculator. Round your answer to the nearest tenth.

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boffeemadrid

Answer:

The magnitude of the earthquake that is 1000 times more intense than a standard earthquake=3.0

Step-by-step explanation:

The magnitude "M" of an earthquake is defined as:

[tex]M=log\frac{I}{S}[/tex]                                                                             (1)

where  I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a “standard” earthquake, which is barely detectable.

If  the magnitude of an earthquake that is 1000 times more intense than a standard earthquake, then intensity of Earthquake=1000S

Now, Substituting the value of the intensity of the Earthquake in equation (1), we get

[tex]M=log(\frac{1000S}{S})[/tex]

=[tex]log(1000)[/tex]

=3.0

Therefore,  The magnitude of the earthquake that is 1000 times more intense than a standard earthquake=3.0

raphealnwobi

The magnitude of an earthquake that is 1,000 times more intense than a standard earthquake is 3.

Given the equation:

M =log (l/S)

Where M is the magnitude of the earthquake, I is the intensity of the earthquake and S is the intensity of a standard earthquake.

For an earthquake with 1,000 times more intense than a standard earthquake. Hence:

I = 1000S

Hence:

M =log (l/S)

M = log (1000S/S) = log (1000)

M = 3

The magnitude of an earthquake that is 1,000 times more intense than a standard earthquake is 3.

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