Answer:
x = 6 and y = 0 → (6, 0)
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}2x+3y=12\\x-y=6&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}2x+3y=12\\3x-3y=18\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad5x=30\qquad\text{divide both sides by 5}\\.\qquad\boxed{x=6}\\\\\text{Put the value of x to the second equation}\\\\6-y=6\qquad\text{subtract 6 from both sides}\\-y=0\to\boxed{y=0}[/tex]
