Answer:
[tex]h=\frac{v^2}{2g}[/tex]
Explanation:
In absence of non-conservative forces, the mechanical energy of the object (sum of kinetic energy) is conserved:
[tex]K_i + U_i = K_f + U_f[/tex]
where:
[tex]K_i = \frac{1}{2}mv^2[/tex] is the initial kinetic energy of the object, with mass m and launched with speed v upward
[tex]U_i = 0[/tex] is the initial potential energy of the object, which is zero since the object is launched from the ground
[tex]K_f = 0[/tex] is the kinetic energy of the object when it reaches its maximum height, and it is zero because at maximum height the speed is zero: v = 0
[tex]U_f = mgh[/tex] is the potential energy of the object at maximum height h, with g being the acceleration due to gravity
Therefore, the previous equation becomes
[tex]\frac{1}{2}mv^2=mgh[/tex]
and by re-arranging it we find an expression for the maximum height:
[tex]h=\frac{v^2}{2g}[/tex]