Respuesta :
There is 10 digits to choose from and 26 letters.
Multiply the 3 choices together for total combinations: 10 x 10 x 26 = 2600.
The probability pf picking the first digit would be 1/10
The probability of picking the 2nd digit would also be 1/10
The probability of picking the letter would be 1/26
Answer:
- If repetition is allowed then the number of ways of making a pass code =[tex]2600[/tex]
- The probability of choosing the first digit correctly = [tex]\dfrac{1}{10}[/tex]
- The probability of choosing the second digit correctly = [tex]\dfrac{1}{10}[/tex]
- The probability of guessing letter correctly = [tex]\dfrac{1}{26}[/tex]
- The probability that you would guess Hector's passcode correctly on the first try =[tex]\dfrac{1}{2600}[/tex]
Step-by-step explanation:
Given: An extra security pass-code for a certain account is made up of 2 digits followed by 1 letter.
The number of choices for first and second place =10
The choices for the third place 26
If repetition is allowed then the number of ways of making a pass code is given by :-
[tex]10\times10\times26=2600[/tex]
The probability of choosing the first digit correctly = [tex]\dfrac{1}{10}[/tex]
Similarly , the probability of choosing the second digit correctly = [tex]\dfrac{1}{10}[/tex]
The probability of guessing letter correctly = [tex]\dfrac{1}{26}[/tex]
If we choose the digits and letters randomly , then the probability that you would guess Hector's passcode correctly on the first tr4=y is given by ;-
[tex]\dfrac{1}{10}\times\dfrac{1}{10}\times\dfrac{1}{26}=\dfrac{1}{2600}[/tex]