Answer:
A
Step-by-step explanation:
The area of a square is A = s². So the area of this square is A = (2x+2)² = 4x² + 8x + 4.
The perimeter of the triangle is 4/3x + 4/3x+4/3x = 12/3x = 4x.
The difference between the two values is subtraction. Subtract the expressions and simplify.
4x² + 8x + 4 -4x = 4x² + 4x + 4
This expression is also equal to 3. Set it equal to 3 and solve for x.
4x² + 4x + 4 = 3
4x² + 4x + 1 = 0
Substitute a = 4, b = 4 and c = 1 into the quadratic formula.
The quadratic formula is [tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex].
Substitute and you'll have:
[tex]x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-4+/-\sqrt{4^2-4(4)(1)} }{2(4)}=\frac{-4+/-\sqrt{16-16} }{8)}[/tex]
[tex]\frac{-4+/-\sqrt{0} }{8} = \frac{-4}{8}=\frac{-1}{2}[/tex]
