Answer:
Graphic attached
Step-by-step explanation:
The oblique asymptote of the function has the shape of a line of the form
[tex]y = mx + b[/tex]
We need to find the slope m and the intercept b.
The oblique asymptote is found by these two limits:
[tex]m = \lim_{x \to \infty}\frac{f(x)}{x}\\\\b = \lim_{x \to \infty}[f(x) - mx][/tex]
If [tex]f(x) = \frac{(2x+3)(x-6)}{(x+2)(x-1)}[/tex] then:
[tex]m = \lim_{x \to \infty} \frac{\frac{(2x+3)(x-6)}{(x+2)(x-1)}}{x}\\\\m = \lim_{x \to \infty} \frac{2x^2-9x-18}{x^3 +x^2 -2x}\\\\m = 0[/tex]
The slope is 0. Therefore the function has no oblique asymptote.
Horizontal asymptote:
[tex]y = 2[/tex]
Vertical asymptote
[tex]x = -2\\x = 1[/tex]
