Respuesta :

ShyzaSling

Answer:

y = -5x - 21

Step-by-step explanation:

Given in the question,

equation of a parallel line

y = -5x + 6

point through which it passes

(-4,-1)

Step1

Find the gradient of the equation given, as it is parallel so it will have same gradient

equation of straight line

y = mx + c

where m is gradient

            c is y intercept

y = -5x + 6

m =-5

Step2

Find y-intercept

-1 = -5(-4) + c

-1 = 20 + c

c = -20 - 1

c = -21

Step3

form the equation

y = -5x - 21

kudzordzifrancis

Answer:

[tex]y=-5x-21[/tex]

Step-by-step explanation:

The given line has equation;

[tex]y=-5x+6[/tex]

This line is in the form  [tex]y=mx+c[/tex], where [tex]m=-5[/tex]

[tex](x_1,y_1)=(-4,-1)[/tex]

The required equation can be found using the formula;

[tex]y-y_1=m(x-x_1)[/tex]

We substitute the given point and slope to get,

[tex]y+1=-5(x+4)[/tex]

Expand

[tex]y=-5x-20-1[/tex]

[tex]y=-5x-21[/tex]

Otras preguntas