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write an algebraic expression for this word problem. An orange contains 62 calories which is x fewer calories than a nectarine. How many calories does a nectarine have?

Respuesta :

TaeKwonDoIsDead

Answer:

n = 62 + x

Step-by-step explanation:

From the problem given, it is clear that the orange has LESS calories than a nectarine. HOW much less? "x" less.

Also, orange has 62 calories. So, nectarine MUST HAVE 62 + x calories.

If we let nectarine's calories be n, we can write:

n = 62 + x

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