Answer:
13.9 m/s
Explanation:
The velocity of the train along the inclined surface is given by the ratio between the distance travelled, d, and the time taken, t:
[tex]v=\frac{d}{t}[/tex]
where we have
d = 400 m
t = 5 s
Substituting,
[tex]v=\frac{400 m}{5 s}=80 m/s[/tex]
This is the velocity of the train along the inclined plane. Now we can find the vertical component of the velocity by using the formula:
[tex]v_y = v sin \theta[/tex]
where [tex]\theta=10^{\circ}[/tex] is the angle of the slope. Substituting, we find
[tex]v_y = (80 m/s)(sin 10^{\circ})=13.9 m/s[/tex]
