For this case we have the following system of equations:
[tex]4x + 5y = -4\\4x + 3y = 12[/tex]
We multiply the second equation by -1:
[tex]-4x-3y = -12[/tex]
We add the equations:
[tex]4x-4x + 5y-3y = -4-12\\5y-3y = -4-12\\2y = -16\\y = \frac {-16} {2}\\y = -8[/tex]
We find the value of "x":
[tex]4x = 12-3y\\x = \frac {12-3y} {4}\\x = \frac {12-3 (-8)} {4}\\x = \frac {12 + 24} {4}\\x = \frac {36} {4}\\x = 9[/tex]
Thus, the solution of the system is given by:
[tex](x, y) :( 9, -8)[/tex]
ANswer:
(9, -8)
