Answer:
Step-by-step explanation:
[tex]3x-3<9\qquad\text{add 3 to both sides}\\3x-3+3<9+3\\3x<12\qquad\text{divide both sides by 3}\\\dfrac{3x}{3}<\dfrac{12}{3}\\\boxed{x<4}\\\\============================\\\\5x+2<32\qquad\text{subtract 2 from both sides}\\5x+2-2<32-2\\5x<30\qquad\text{divide both sides by 5}\\\dfrac{5x}{5}<\dfrac{30}{5}\\\boxed{x<6}[/tex]