In a game of football outdoors on a cold day, a player will begin to feel exhausted after using approximately 8.0 × 105 J of internal energy. (a) One player, dressed too lightly for the weather, has to leave the game after losing 6.8 × 105 J of heat. How much work has he done? (b) Another player, wearing clothes that offer better protection against heat loss, is able to remain in the game long enough to do 2.4 × 105 J of work. What is the magnitude of the heat that he has lost?

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aristocles aristocles · Answer 1 · 2019-07-06T04:03:17+02:00

Answer:

Part a)

[tex]W = 1.2 \times 10^5 J[/tex]

Part b)

[tex]Q = 5.6 \times 10^5 J[/tex]

Explanation:

It given that player will feel exhausted when he is using his internal energy of [tex]8.0 \times 10^5 J[/tex]

PART a)

it is given that heat loss by the player is given as

[tex]Q = 6.8 \times 10^5 J[/tex]

now by first law of thermodynamics we have

[tex]\Delta U = Q + W[/tex]

now we have

[tex]8.0 \times 10^5 = 6.8 \times 10^5 + W[/tex]

[tex]W = 1.2 \times 10^5 J[/tex]

PART b)

It is given that another player did the work as

[tex]W = 2.4 \times 10^5 J[/tex]

now we have first law of thermodynamics

[tex]\Delta U = Q + W[/tex]

now we have

[tex]8.0 \times 10^5 = 2.4 \times 10^5 + Q[/tex]

[tex]Q = 5.6 \times 10^5 J[/tex]