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In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. If the angular velocity of the ball about the elbow joint is 30.0 rad/s and the ball is 1.30 m from the elbow joint, what is the velocity of the ball?

Respuesta :

MathPhys

Answer:

39.0 m/s

Explanation:

Linear velocity = angular velocity × radius

v = ωr

v = (30.0 rad/s) (1.30 m)

v = 39.0 m/s

onyebuchinnaji

The linear velocity of the ball is 39 m/s.

The given parameters;

  • angular velocity of the ball about the elbow, ω = 30 rad/s
  • the distance of the ball from the elbow joint, r = 1.3 m

The velocity of the ball is the tangential velocity of the ball along the circular path of the elbow joint.

v =  ωr

where;

  • v is the linear velocity (m/s)
  • ω is the angular velocity (rad/s)
  • r is the radius of the circular path (m)

Substitute the given parameters and solve for the value of v;

v = (30 rad/s) x (1.3 m)

v = 39 m/s

Thus, the linear velocity of the ball is 39 m/s.

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