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A composite wall 8 m long and 4 m high consists of 4 cm of brick, 8 cm of concrete, 6 cm of fiberglass and 10 cm of corkboard. The inside temperature is 18°C, and the outside temperature is 40°C. How much heat is flow into the house through this wall in 10 hours?

Respuesta :

Answer:

Heat flow through walls in 10 hours is

[tex]Q = 6.1 \times 10^6 J[/tex]

Explanation:

Thermal conductivity of all the materials is as follows

1). Concrete = 0.8

2). Brick = 0.6

3). Fibreglass = 0.04

4). Corkboard = 0.04

Area of the wall is given as

[tex]A = (8 \times 4) = 32 m^2[/tex]

now the thermal resistance due to each wall is given as

[tex]R_1 = \frac{0.04}{0.6(32)} = 2.08 \times 10^{-3}[/tex]

[tex]R_2 = \frac{0.08}{0.8(32)} = 3.125 \times 10^{-3}[/tex]

[tex]R_3 = \frac{0.06}{0.04(32)} = 46.87 \times 10^{-3}[/tex]

[tex]R_2 = \frac{0.10}{0.04(32)} = 78.13 \times 10^{-3}[/tex]

Now total thermal resistance of all walls

[tex]R = R_1 + R_2 + R_3 + R_4[/tex]

[tex]R = (2.08 + 3.125 + 46.87 + 78.13) \times 10^{-3}[/tex]

[tex]R = 0.130[/tex]

now rate of heat transfer per second is given as

[tex]\frac{dQ}{dt} = \frac{T_1 - T_2}{R}[/tex]

[tex]Q = \frac{40 - 18}{0.130}(10 \times 3600)[/tex]

[tex]Q = 6.1 \times 10^6 J[/tex]