Answer:350.92 KJ/kg
Explanation:
Given the process is reversible adiabatic i.e it is isentropic
[tex]P_1=5 MPa [/tex]
[tex]T_1=4500 MPa[/tex]
[tex]P_2=1.4 MPa[/tex]
From steam table
[tex]h_1=3317.03KJ/kg[/tex]
For isentropic process [tex]s_1=s_2[/tex]
at [tex]P_2=1.4 MPa[/tex]
[tex]s_2=6.82 KJ/kg-k[/tex]
[tex]h_2=2966.11 KJ/kg[/tex]
Therefore Work output of the turbine per unit mass of steam is =[tex]h_1-h_2[/tex]
=3317.03-2966.11
=350.92 KJ/kg
