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a superconducting solenoid is to be designed to generate a magnetic field of 10 t if the solenoid winding has 2000 turns meter what is the required current

Respuesta :

Answer:

3981 A

Explanation:

B = 10 t

n = 2000 per metre

Let the current is i

Use the formula for the magnetic field due to a current carrying solenoid

B = μo n i

10 = 4 x 3.14 x 10^-7 x 2000 x i

i = 3980.9 A = 3981 A

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