Answer:
82.8986 km
Explanation:
Given:
Pressure = 7.00×10⁻¹³ atm
Since , 1 atm = 101325 Pa
So, Pressure = 7.00×10⁻¹³×101325 Pa = 7.09275×10⁻⁸ Pa
Radius = 2.00×10⁻¹⁰ m
Diameter = 4.00×10⁻¹⁰ m (2× Radius)
Temperature = 303 K
The expression for mean free path is:
[tex]\lambda (Mean\ free\ path)=\frac {K (Boltzmann\ Constant)\times Temperature}{\sqrt {2}\times \pi\times (Diameter)^2\times Pressure}[/tex]
Boltzmann Constant = 1.38×10⁻²³ J/K
So,
[tex]\lambda (Mean\ free\ path)=\frac {1.38\times 10^{-23}\times 303}{\sqrt {2}\times \frac {22}{7}\times (4.00\times 10^{-10})^2\times 7.09275\times 10^{-8}}[/tex]
Mean free path = 82.8986×10³ m = 82.8986 km