If the interplanar distance in the crystal is 287 pm , and the angle of maximum reflection is found to be 7.29 ∘, what is the wavelength of the x-ray beam? (Assume n=1.)

Respuesta :

Answer:

72.83 pico meter

Explanation:

As per Brags equation :

nλ=2dsinθ

now n=1

      θ = 7.29

      d= 287 pm

     λ = 2dsinθ / n

       = 72.83 pico meter

Answer:[tex]\lambda =72.83 pm[/tex]

Explanation:

Given

Interplanar distance [tex]\left ( d\right )=287 pm[/tex]

Maximum angle of reflection=[tex]7.29^{\circ}[/tex]

By Bragg's law

d=[tex]\frac{\lambda }{2sin\theta}[/tex]

Where [tex]\lambda [/tex]=wavelength of x-ray beam

[tex]287\times 10^{-12}=\frac{\lambda }{2sin\left ( \theta\right )}[/tex]

[tex]\lambda =287\times 10^{-12}\times 2\times sin\left ( 7.29\right )[/tex]  

[tex]\lambda =72.83 pm [/tex]