If a tablet of acetaminophen, C8H9NO2, weighs 324 mg, how many moles are there in the tablet? If a tablet of acetaminophen, C8H9NO2, weighs 324 mg, how many moles are there in the tablet? 2.15 × 10-3 4.89 × 104 48.9 466 2.15

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Answer:

[tex]2.14*10^{-3} mol[/tex]

Explanation:

number of moles of C8H9NO2 = [tex]\frac{mass}{molar mass}=\frac{324*10^{-3} g}{151.163g/mol}=2.14*10^{-3}mol[/tex]

The trick is to remember to convert milligrams to grams because molar mass is normally presented in grams per mole

The number of mole present in 324 mg of acetaminophen, C₈H₉NO₂, is 2.15×10¯³ mole

The mole of a substance is related to it's mass and molar mass according to the following equation:

[tex]Mole = \frac{mass}{molar mass}\\\\[/tex]

With the above formula, we can obtain the number of mole C₈H₉NO₂. This is illustrated below:

Mass of C₈H₉NO₂ = 324 mg = 324×10¯³ g = 0.324 g

Molar mass of C₈H₉NO₂ = (12×8) + (1×9) + 14 + (16×2) = 151 g/mol

Mole of C₈H₉NO₂ =?

[tex]Mole = \frac{mass}{molar mass } \\\\= \frac{0.324}{151} \\\\[/tex]

Mole of C₈H₉NO₂ = 2.15×10¯³ mole

Therefore, 2.15×10¯³ mole is present in 324 mg of C₈H₉NO₂

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