Answer:
maximum powr attained when resistor arrange in series and equal tp 143.86 w
Explanation:
WE HAVE FOUR CASES TO OBTAINED MAXIMUM POWER
we know that
Maximum current [tex]= \sqrt({P}{R})[/tex]
[tex]I = \sqrt\frac{48}{2.4}v[/tex]
I= 4.47 volt
case 1 - arrange in series
equivalent resistance [/tex]= 3R = 3*2.4 = 7.2 \ohm[/tex]
[tex]power = 4.47^2 *7.2 = 143.86 w[/tex]
case 2 connected in parallel
[tex]R_EQUI = \frac{1}{\frac{1}{2.4}+\frac{1}{2.4}+\frac{1}{2.4}}[/tex]
[tex]R_EQUI = 0.80 \ohm[/tex]
power = 0.80* 4.47^2 = 15.98 w
case 3 two in series and one in parallel
[tex]R _equi = \frac{(2.4+2.4)*2.4}{4.8+2.4} = 1.6\ohm[/tex]
[tex]power = 4.47^2 *1.6 = 31.96 w[/tex]
case 4
one in series and two in parallel
[tex]R_equi = \frac{2.4*2.4}{2.4+2.4} +2.4 = 2.88 \ohm[/tex]
[tex]power = 4.47^2*2.88 = 57.54 w[/tex]
