contestada

in a​ lottery, the top cash prize was ​$670 ​million, going to three lucky winners. players pick four different numbers from 1 to 53 and one number from 1 to 42. a player wins a minimum award of $ 600 by correctly matching three numbers drawn from the white balls​ (1 through 53​) and matching the number on the gold ball​ (1 through 42​). what is the probability of winning the minimum​ award?

Respuesta :

Answer:[tex]\frac{^4C_3\cdot ^49C1}{^53C_4}\times \frac{1}{42}[/tex]

Step-by-step explanation:

Player choose 4 numbers from white balls numbered 1 to 53 and

1 number from gold ball numbered 1 to 42

He has to choose 3 correct number out of 4 numbers in white ball

and 1 number from gold balls

he can do in [tex]^4C_3\cdot ^49C_1[/tex] and 1  ways respectively

therefore Probability =[tex]\frac{^4C_3\cdot ^49C1}{^53C_4}\times \frac{1}{42}[/tex]

Otras preguntas