x ≈ 2.76,
x ≈ 7.24
How to quickly solve a quadratic equation?
ax2+c=0 is the pure quadratic equation. To solve it , bring the constant term the RHS (right hand side) or divide both side by a, coefficient of the x2 or take the square root. Bring the equation ax2+c=0 in the form p2-q2 =0. Use the p2-q2= (p+q) (p-q).
How do you solve a quadratic equation?
- Write a equation in the form of, ax2 +bx +c = 0 a x 2 + b x + c = 0
- Factorize the quadratic and solve for a variable.
- Use quadratic formula if we could not factorize the quadratic.
- Quadratic formula: x = −b± b2−4ac√ 2a x = − b ± b 2 − 4 a c 2 a
Step-by-step explanation:
Given
x² - 10x + 20 = 0 ( subtract 20 from both sides )
x² - 10x = - 20
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2( - 5)x + 25 = - 20 + 25
(x - 5)² = 5 ( take the square root of both sides )
x - 5 = ± [tex]\sqrt{5}[/tex] ( add 5 to both sides )
x = 5 ± [tex]\sqrt{5} \\[/tex]
Hence
x = 5 -[tex]\sqrt{5}[/tex] ≈ 2.76
x = 5 + [tex]\sqrt{5}[/tex]≈ 7.24
Learn more about quadratic equation here https://brainly.com/question/17177510
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