Answer:
29.44 grams
Explanation:
Molar Mass of NH2NO3 = Molar Mass of Nitrogen + 2(Molar Mass of Hydrogen) + Molar Mass of Nitrogen + 3(Molar Mass of Oxygen)
Molar Mass of NH2NO3 = 14 + 2(1) + 14 + 3(16) = 78 grams
Mass of Nitrogen in NH2NO3 = 14 + 14 = 28 grams
Percentage by mass of Nitrogen in NH2NO3 = [tex]\frac{28}{78} \times 100\% =35.90 \%[/tex]
This means, the percentage of Nitrogen in NH2NO3 is 35.90%. So the amount of Nitrogen in 82 g of NH2NO3 will be 35.90% of 82
35.90% of 82 = 0.359 x 82 = 29.44 grams.
Thus, 29.44 grams of Nitrogen will be present in 82 grams of NH2NO3
