Determine the mass of each of t he following:
(a)2.345 mol LiCl
(b)0.0872 mol acetylene, C2H2
(c)3.3 x 10-2 mol NA2 CO3
(d)1.23 x 103 mol fructose, C6H12O6
(e)0.5758 mol FeSO4(H2O)7

Respuesta :

Explanation:

Mass of compounds = Moles of compound × Molecular mass of compound

a) Moles of LiCl = 2.345 mol

Molecular mass of LiCl = 42.5 g/mol

Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g

b) Moles of acetylene = 0.0872 mol

Molecular mass of acetylene= 26 g/mol

Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g

c) Moles of sodium carbonate= [tex]3.3\times 10^{-2}mol[/tex]

Molecular mass of sodium carbonate= 106 g/mol

Mass of  [tex]3.3\times 10^{-2}mol[/tex] sodium carbonate

=  [tex]3.3\times 10^{-2}mol\times 106 g/mol[/tex]= 3.498 g

d) Moles of fructose = [tex]1.23\times 10^3 mol[/tex]

Molecular mass fructose= 180 g/mol

Mass of  [tex]1.23\times 10^3 mol[/tex] fructose

=  [tex]1.23\times 10^3mol\times 180 g/mol = 221,400 g[/tex]

e) Moles of  [tex]FeSO_4(H_2O)_7=0.5758 mol[/tex]

Molecular mass of [tex]FeSO_4(H_2O)_7 =278 g/mol[/tex]

Mass of  [tex]1.23\times 10^3 mol[/tex] fructose

=  [tex]0.5758 mol\times 278 g/mol= 160.0724 g[/tex]