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Consider this question: What is the mass of the solute in 0.500 L 0.30
M glucose C6H12O6, used for intravenous injection?
(a)Outline the steps necessary to answer this question
(b)answer the question

Respuesta :

Willchemistry

Hey there!:

a )

number of moles of solute :

moles of solute = molarity  x volume ( L )

moles of solute = 0.30 x 0.500

moles of solute =  0.15 moles of glucose

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b) Molar mass of glucose : 180.156 g/mol

1 mole glucose ----------------- 180.156 g

0.15 moles ---------------------- ( mass glucose ) ?

mass glucose = 0.15 x 180.156 / 1

mass glucose => 27.0234 g

dsdrajlin

The mass of the solute in 0.500 L of a 0.30 M glucose solution is 27 g.

The steps to calculate it are:

  1. Use the definition of molarity to calculate the moles of glucose.
  2. Use the molar mass of glucose to convert moles to mass.

We want to calculate the mass of the solute (glucose) in 0.500 L of a 0.30 M glucose solution. The required steps are:

  1. Use the definition of molarity to calculate the moles of glucose.
  2. Use the molar mass of glucose to convert moles to mass.

  • Step 1: Use the definition of molarity to calculate the moles of glucose.

Molarity is defined as the moles of a solute per liters of a solution.

M = moles of solute / liters of solution

moles of solute = M × liters of solution = 0.30 mol/L × 0.500 L = 0.15 mol

  • Step 2: Use the molar mass of glucose to convert moles to mass.

The molar mass of glucose is 180.16 g/mol.

0.15 mol × 180.16 g/mol = 27 g

The mass of the solute in 0.500 L of a 0.30 M glucose solution is 27 g.

The steps to calculate it are:

  1. Use the definition of molarity to calculate the moles of glucose.
  2. Use the molar mass of glucose to convert moles to mass.

Learn more about molarity here: https://brainly.com/question/9149034

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